At the risk of being wrong.... (I'm always ready to learn something
new) - and seemingly I'm only too happy to be wrong!...
And... it might even be that it is exactly the same result - but I
would have proposed;
SELECT
R.region_name,
Count(*) AS RegionComplaints
FROM
Region AS R
LEFT JOIN City AS Ci
LEFT JOIN Complaint AS Cm ON Ci.id = Cm.city_id
ON R.id = C.region_id
GROUP BY
R.region_name;
Gavin.
On 17/06/2009, at 7:25 AM, Richard Broersma wrote:
On Tue, Jun 16, 2009 at 1:59 PM, Carol
Cheung<cache...@consumercontact.com> wrote:
I would like to find the counts of complaints by region and I would
like all
regions to be displayed, regardless of whether or not complaints
exist for
that region. Is left outer join what I'm looking for?
SELECT R.region_name, Count(*) AS RegionComplaints
FROM Region AS R
LEFT JOIN City AS Ci
ON R.id = C.region_id
LEFT JOIN Complaint AS Cm
ON Ci.id = Cm.city_id
GROUP BY R.region_name;
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Regards,
Richard Broersma Jr.
Visit the Los Angeles PostgreSQL Users Group (LAPUG)
http://pugs.postgresql.org/lapug
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As always Please contact me if I can be of any further assistance.
Gavin "Beau" Baumanis
Senior Application Developer
PalCare P/L
657 Nicholson Street
Carlton North
Victoria, Australia, 3054
E: b...@palcare.com.au
P: +61 -3 9380 3513
M: +61 -438 545 586
W: http://www.palcare.com.au
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