> 2010/8/18 Horváth Imre <horvath.i...@blemidon.hu>:
>> It don't work...
A function returning a scalar type cannot control the column name
assigned to the scalar in the calling query. To do that, you need to
return a composite type, which means there need to be at least two OUT
parameters if you're trying to do it via OUT-parameter names.
regards, tom lane
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