Unless I overlooked something here, does this work ?

SELECT no, name, MAX(similarity(name, 'Tooneyvara')) AS sim
FROM vtown
WHERE similarity(name, 'Tooneyvara') > 0.4
GROUP BY no, name
ORDER BY sim DESC

--
Robins Tharakan

On 11/08/2011 02:50 AM, Tarlika Elisabeth Schmitz wrote:
Hello,

I would like to GROUP the result by one column and ORDER it by another:

SELECT
     no, name, similarity(name, 'Tooneyvara') AS s
     FROM vtown
     WHERE    similarity(name, 'Tooneyvara')>  0.4
     ORDER BY s DESC

Result:

1787    "Toomyvara"   0.5
1787    "Toomevara"   0.4
1188    "Toonybara"   0.4


Desired result:

1787    "Toomyvara"   0.5
1188    "Toonybara"   0.4

Gets rid of the  duplicate "no" keeping the spelling with the greater
similarity and presents the remaining result ordered by similarity.


My solution:

SELECT * FROM
(
SELECT DISTINCT ON (no)
     no, name,
     similarity(name, 'Tooneyvara') AS sim
     FROM vtown
     WHERE similarity(name, 'Tooneyvara')>  0.4
     ORDER BY no, sim DESC
) AS x
ORDER BY sim


Is that the best way to achieve this result?

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