>________________________________________
>Von: pgsql-sql-ow...@postgresql.org [pgsql-sql-ow...@postgresql.org]" im
>Auftrag von "Venky >Kandaswamy [ve...@adchemy.com]
>
>You can use Postgres WINDOW functions for this in several different ways. For
>example, one way of doing it:
>
>select stts_id, last_value(stts_offset) over (partition by stts_id order by
>stts_offset desc)
> + last_value(stts_duration) over (partition by stts_id order
> by stts_offset desc)
>from table
>group by stts_id;
another simple solution with distinct on:
select distinct on (stts_id, stts_offset) stts_id, stts_offset+stts_duration
from table
order by stts_id, stts_offset desc
Marc Mamin
________________________________________
From: pgsql-sql-ow...@postgresql.org <pgsql-sql-ow...@postgresql.org> on behalf
of Gary Stainburn <gary.stainb...@ringways.co.uk>
Sent: Thursday, July 25, 2013 10:57 AM
To: pgsql-sql@postgresql.org
Subject: Re: [SQL] value from max row in group by
As usual, once I've asked the question, I find the answer myself.
However, it *feels* like there should be a more efficient way. Can anyone
comment or suggest a better method?
timetable=> select stts_id, stts_offset+stts_duration as total_duration
timetable-> from standard_trip_sections
timetable-> where (stts_id, stts_offset) in
timetable-> (select stts_id, max(stts_offset) from standard_trip_sections
group by stts_id);
stts_id | total_duration
---------+----------------
1 | 01:35:00
2 | 01:35:00
3 | 01:08:00
4 | 01:38:00
5 | 01:03:00
6 | 01:06:00
(6 rows)
timetable=>
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