I am answering my own question because I found the solution for it.
This is the code that didn't work:
> myString := 'one\n\ntwo\n\n'.
> re := '\n\n' asRegex.
> myString splitOn: re.
The reason it didn't work was because you apparently have to escape the
newlines pattern in the regex line. So the correct (working) example is
here:
> myString := 'one\n\ntwo\n\n'.
> re := '\\n\\n' asRegex.
> myString splitOn: re.
I am putting this on here just in case someone else runs into the same
problem.
- Steve
On 01/14/2019 09:06 AM, Steve Quezadas wrote:
I am trying to split a string in pharo using a regular expression.
A simple example that works:
myString := 'one\n\ntwo\n\n'.
myString splitOn: '\n\n'.
A simple example that does not work:
myString := 'one\n\ntwo\n\n'.
re := '\n\n' asRegex.
myString splitOn: re.
The result of the above is I get the regular old string back
('one\n\ntwo\n\n'). I went through the source code and it should be able
to handle a regex object:
> "splitter - can be a subsequence, a Block or a Regex (String receiver
> only). Any other object used as a splitter is treated as an Array
> containing that object."
I am baffled as to why it's not working. is there something simple I am
missing?
- Steve
