Actually this isn’t quite so simple - as the problem outline below compounds 
itself by the use of #average (which uses #sum and not #sumNumbers) and thus 
gives a less precise answer.

Why wouldn’t #average use #sumNumbers inside? Or does there need to be 
#averageNumbers as a complement …. Argggg it makes my head hurt.

Its important as we compare differently to python and this then makes us waste 
time.

Tim

> On 20 Mar 2020, at 15:19, Tim Mackinnon <tim@testit.works> wrote:
> 
> Actually I can answer my own question - its the difference between #sum and 
> #sumNumbers (and an easy mistake to make - I almost wish that sum was the 
> sumNumbers implementation and there was a sumSample that behaved like now)
> 
>> On 20 Mar 2020, at 14:52, Tim Mackinnon <tim@testit.works 
>> <mailto:tim@testit.works>> wrote:
>> 
>> Hi guys - I recall this came up a few months ago, but I’m curious about the 
>> difference of Pharo’s use of Float64 vs Python - as I assumed that if 
>> languages use the same IEEE spec (or whatever spec it is) that simple stuff 
>> would be quite similar.
>> 
>> I am curious why in Python adding these numbers:
>> 
>> y = 987.9504418944 + 815.2627636718801 + 1099.3898999037601 + 
>> 1021.6996069333198 + 1019.8750146478401 + 1084.5603759764 + 
>> 1008.2985131833999 + 1194.9564575200002 + 893.9680444336799 + 
>> 1032.85460449136 + 905.9324633786798 + 1024.2805590819598 + 
>> 784.5488305664002 + 957.3522631840398 + 1001.7526196294
>> print(y)
>> print(y / 15)
>> 
>> Gives:
>> 
>> 14832.682458496522
>> 988.8454972331015
>> 
>> In pharo I have noticed an anomaly which I thought was precision but it may 
>> be something odd with iterators.
>> 
>> y := 987.9504418944 + 815.2627636718801 + 1099.3898999037601 + 
>> 1021.6996069333198 + 1019.8750146478401 + 1084.5603759764 + 
>> 1008.2985131833999 + 1194.9564575200002 + 893.9680444336799 + 
>> 1032.85460449136 + 905.9324633786798 + 1024.2805590819598 + 
>> 784.5488305664002 + 957.3522631840398 + 1001.7526196294.
>> y.
>> y / 15.
>> 
>> Gives the same as Python.
>> 
>> BUT:
>> 
>> z := {987.9504418944 . 815.2627636718801 . 1099.3898999037601  . 
>> 1021.6996069333198  . 1019.8750146478401 . 1084.5603759764 . 
>> 1008.2985131833999 . 1194.9564575200002 . 893.9680444336799 . 
>> 1032.85460449136 . 905.9324633786798 . 1024.2805590819598 . 
>> 784.5488305664002 . 957.3522631840398 . 1001.7526196294} sum.
>> z.
>> z / 15.
>> 
>> Gives
>> 14832.68245849652
>> 988.8454972331014
>> 
>> Is this correct?
>> 
>> 
> 

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