On Sun, 20 Jun 2010 06:18:46 +0900, Philippe Sigaud
<[email protected]> wrote:
Andrei:
this(U)(U another) if (is(U == Tuple!(V), V...)) { ... }
Sean:
Is that 'is' syntax correct?
No, halas you can't put a V... inside an is expression. Only is(U ==
Tuple!V, V) is authorized.
To detect a Tuple, I use the following workaround: std.typecons.Tuple
has a
.Types member, so test for it (and btw .Types will give you the V tuple):
this(U)(U another) if (is(U.Types)) // U is a Tuple
{
alias U.Types V;
...
}
also, testing for U.stringof beginning with "Tuple!("... But I don't like
this.
I use following isTuple.
template isTuple(T)
{
enum isTuple = __traits(compiles, { void f(X...)(Tuple!X t) {};
f(T.init); });
}
Masahiro
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