ID: 16459 Updated by: [EMAIL PROTECTED] Reported By: [EMAIL PROTECTED] -Status: Open +Status: Bogus Bug Type: Feature/Change Request Operating System: Win*/Slackware PHP Version: 4.1.2 New Comment:
Sorry, i missed the constant "__FILE__". Previous Comments: ------------------------------------------------------------------------ [2002-04-05 19:07:48] [EMAIL PROTECTED] There doesn't appear to be a way to get the filename of code that is currently executing. Eg. echo $SCRIPT_FILENAME; or echo $PHP_SELF; works fine in most situations, but as soon as the file containing this code is included in another, they start to return the filename of the includING file. (not the includED one). I understand this generally goes against the purpose of include() but this functionality would be very useful. Thanks ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=16459&edit=1
