#42961 [Opn]: mysqli would not return result values within "for" loop.

[wilsonwg at gmail dot com]

 ID:               42961
 User updated by:  wilsonwg at gmail dot com
 Reported By:      wilsonwg at gmail dot com
 Status:           Open
 Bug Type:         MySQLi related
 Operating System: Windows XP SP2
 PHP Version:      5.2.4
 New Comment:

I forgot to add under score in my result sections.

SELECT * FROM compounds where compound_name = 'item 1'

Should be:
SELECT * FROM compounds where compound_name = 'item_1'


Previous Comments:
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[2007-10-14 11:20:13] wilsonwg at gmail dot com

Description:
------------
I set up an array in the code and then use the for loop to query my
database. However, the mysqli functions would not return the result
values.

This is the table used for the query(columns separated a comma):

-------------
id, item_name
-------------
1, item_1
2, item_2
3, item_3
4, item_4
------------- 




Reproduce code:
---------------
$mysqli_connect =mysqli_connect("localhost", "root", "password",
"myDB");   

  $array_items = "item_1,item_2,item_3,item_4";
  $array_list = explode (",", $array_items);
  
  for ($i=0; $i<count($array_list); $i++){           

  $select_item = "SELECT * FROM compounds where item_name =
'".$array_list[$i]."'";
  
  echo "$select_item <p>";
  
  $search_item_query = mysqli_query($mysqli_connect, $select_item);
  
  $result = mysqli_fetch_array($search_item_query);
  
  $id = $result['item_id']; 
  echo "$id <p>";          
}

Expected result:
----------------
SELECT * FROM compounds where compound_name = 'item 1'

1

SELECT * FROM compounds where compound_name = 'item 2'

2

SELECT * FROM compounds where compound_name = 'item 3'

3

SELECT * FROM compounds where compound_name = 'item 4'

4

Actual result:
--------------
SELECT * FROM compounds where compound_name = 'item 1'

SELECT * FROM compounds where compound_name = 'item 2'

SELECT * FROM compounds where compound_name = 'item 3'

SELECT * FROM compounds where compound_name = 'item 4'



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