ID: 40870
Updated by: [EMAIL PROTECTED]
Reported By: key88sf at gmail dot com
-Status: No Feedback
+Status: Feedback
Bug Type: MySQLi related
Operating System: Windows Vista
PHP Version: 5.2.1
New Comment:
Can't reproduce with either current 5.2 CVS or 5.2.1 release code
(see test case below). I tested with MySQL 5.0.45 server and client
library code, which MySQL versions did you see these problems?
--TEST--
Bug #40870 Stored proc warning 1329 produces NULL result set
--SKIPIF--
<?php if (!extension_loaded("mysqli")) print "skip"; ?>
--FILE--
<?php
$mysqli = mysqli_init();
$mysqli->real_connect('localhost', 'root', '', 'test');
if (mysqli_connect_errno())
{
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
$mysqli->query("DROP TABLE IF EXISTS p1") or die($mysqli->error);
$mysqli->query("DROP PROCEDURE IF EXISTS p1") or die($mysqli->error);
$mysqli->query("CREATE PROCEDURE p1() BEGIN DECLARE foo INTEGER DEFAULT
NULL; SELECT i INTO foo FROM t1; SELECT 23;END") or
die($mysqli->error);
if($mysqli->multi_query ("CALL p1();"))
{
do
{
if($objResult = $mysqli->store_result())
{
while($row = $objResult->fetch_assoc())
{
var_dump($row);
}
$objResult->close();
if($mysqli->more_results())
{
print "----- next result -----------\n";
}
}
else
{
print "no results found";
}
}while ( $mysqli->next_result());
}
else
{
print $mysqli->error;
}
$mysqli->query("DROP PROCEDURE p1") or die($mysqli->error);
$mysqli->close();
?>
--EXPECT--
array(1) {
[23]=>
string(2) "23"
}
----- next result -----------
no results found
Previous Comments:
------------------------------------------------------------------------
[2007-03-29 01:00:01] php-bugs at lists dot php dot net
No feedback was provided for this bug for over a week, so it is
being suspended automatically. If you are able to provide the
information that was originally requested, please do so and change
the status of the bug back to "Open".
------------------------------------------------------------------------
[2007-03-21 10:22:17] [EMAIL PROTECTED]
And the LoginAffiliate procedure, please.
------------------------------------------------------------------------
[2007-03-21 07:52:08] key88sf at gmail dot com
Database table to create (MySQL):
CREATE TABLE affiliates (
affiliate_id int(11) NOT NULL auto_increment,
user_name varchar(32) NOT NULL,
password_hash char(32) NOT NULL,
PRIMARY KEY (affiliate_id),
UNIQUE KEY Index_User_Name (user_name)
) ENGINE=MyISAM DEFAULT CHARSET=utf8;
INSERT INTO affiliates (user_name, password_hash) VALUES( 'test',
'9b93b6ff07bfb6463bd0b5a6e65c4125' );
PHP Script to Demonstrate Bug:
<?php
$dbConnection = mysqli_connect("localhost", "root", "password");
$userName = "test";
$passwordHash = md5("some junk");
$sql = sprintf("CALL LoginAffiliate('%s', '%s')", $userName,
$passwordHash);
$recordSet = mysqli_query( $dbConnection, $sql );
if ( !$recordSet )
{
echo "ERROR:" . strval(mysqli_errno($dbConnection));
}
else
{
echo "SUCCESS";
}
die();
?>
------------------------------------------------------------------------
[2007-03-20 19:35:53] [EMAIL PROTECTED]
Thank you for this bug report. To properly diagnose the problem, we
need a short but complete example script to be able to reproduce
this bug ourselves.
A proper reproducing script starts with <?php and ends with ?>,
is max. 10-20 lines long and does not require any external
resources such as databases, etc. If the script requires a
database to demonstrate the issue, please make sure it creates
all necessary tables, stored procedures etc.
Please avoid embedding huge scripts into the report.
------------------------------------------------------------------------
[2007-03-20 19:26:42] key88sf at gmail dot com
Description:
------------
I have a simple stored procedure in MySQL 5.x. The proc first does a
SELECT INTO query, followed by a regular SELECT to return it's result
set.
The SELECT INTO generates a warning 1329 because no rows were fetched.
However, the final SELECT works properly and returns 1 row.
However, the result returned from mysqli_query() is NULL !
Reproduce code:
---------------
Stored proc is this:
DECLARE v_affiliate_id INTEGER DEFAULT NULL;
-- This SELECT INTO returns 0 rows:
select
affiliate_id INTO v_affiliate_id
from
affiliates
where
user_name = v_user_name
and password_hash = v_password_hash;
if ( v_affiliate_id IS NULL ) THEN
SET v_affiliate_id := -1;
end if;
-- This is the result set row:
select v_affiliate_id;
Expected result:
----------------
When I run this from the MySQL command line, I get 1 row, 1 warning
(1329).
When I run from PHP, I *expect* to see a result set with 1 row.
Actual result:
--------------
When I run from PHP, the result set from mysqli_query() is NULL.
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=40870&edit=1
