ID: 43987
Updated by: [EMAIL PROTECTED]
Reported By: ms419 at freezone dot co dot uk
-Status: Open
+Status: Bogus
Bug Type: Class/Object related
Operating System: Debian
PHP Version: 5.2.5
New Comment:
.
Previous Comments:
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[2008-01-31 10:25:38] [EMAIL PROTECTED]
This is not a bug.
Actually, PHP only accepts:
... instanceof $var
... instanceof $obj->property->...
... instanceof className
... instanceof Foo::bar::...
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[2008-01-31 01:42:32] ms419 at freezone dot co dot uk
Description:
------------
PHP raises a parse error when the second operand of an instanceof
operator is a function call. In my case, the function call,
$relatedTable->getPhpName(), returns the class name as a string, which I
want to determine whether $obj is an instance of.
Reproduce code:
---------------
if (!$obj instanceof $relatedTable->getPhpName())
{
if
(!isset($this->object_references[$relatedTable->getPhpName().'_'.$value]))
{
throw new sfException(sprintf('The object "%s" from
class "%s" is not defined in your data file.', $value,
$relatedTable->getPhpName()));
}
$value =
$this->object_references[$relatedTable->getPhpName().'_'.$value]->getPrimaryKey();
}
Expected result:
----------------
The instanceof operator should determine whether $obj is an instance of
the class name returned by $relatedTable->getPhpName()
Actual result:
--------------
Parse error: syntax error, unexpected '(' in
/home/jablko/public_html/qubit/lib/vendor/symfony/lib/plugins/sfPropelPlugin/lib/propel/sfPropelData.class.php
on line 133
Line 133 is the first line of the reproduce code: if (!$obj instanceof
$relatedTable->getPhpName())
This also raises a parse error: if (!$obj instanceof $relatedPhpName =
$relatedTable->getPhpName())
Parse error: syntax error, unexpected '=' in
/home/jablko/public_html/qubit/lib/vendor/symfony/lib/plugins/sfPropelPlugin/lib/propel/sfPropelData.class.php
on line 133
However the following works:
$relatedPhpName = $relatedTable->getPhpName();
if (!$obj instanceof $relatedPhpName)
{
if
(!isset($this->object_references[$relatedTable->getPhpName().'_'.$value]))
{
throw new sfException(sprintf('The object "%s" from
class "%s" is not defined in your data file.', $value,
$relatedTable->getPhpName()));
}
$value =
$this->object_references[$relatedTable->getPhpName().'_'.$value]->getPrimaryKey();
}
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Edit this bug report at http://bugs.php.net/?id=43987&edit=1