ID: 44675
User updated by: lagunaloire at argentina dot com
Reported By: lagunaloire at argentina dot com
Status: Bogus
Bug Type: Output Control
Operating System: Linux
PHP Version: 5.2.5
New Comment:
I found the problem. The problem is YOU CANNOT CALL exec() FROM A
REQUIRED PHP. That mean if you require("somepage.php"); in somepage.php
you cannot call exec();
Previous Comments:
------------------------------------------------------------------------
[2008-04-08 22:06:42] lagunaloire at argentina dot com
Not not! I mistake! I just put something in the array like this:
$output=array("nothing here", "nothing there");
And I see that but that does not mean what I'm seing that from the
program what I executed! Just I was seing it from the self php script.
Sorry!! =S It is not working still! I don't get filled the array with
the output for the external program.
------------------------------------------------------------------------
[2008-04-08 22:01:15] lagunaloire at argentina dot com
A compilation problem. First I was compiled apache newly and forget to
recompile PHP. I recompiled PHP and it is working now.
------------------------------------------------------------------------
[2008-04-08 21:44:28] lagunaloire at argentina dot com
Description:
------------
The exec() function does not fill the &$output array!
I don't get the output from any program what I try to execute in Safe
mode or not.
Reproduce code:
---------------
exec("program", $output);
print_r($output);
Expected result:
----------------
Array
(
[0] => line1
[1] => line2
[2] => line3
)
Actual result:
--------------
Array () sometimes or nothing at all.
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/?id=44675&edit=1
