ID:               44877
 Updated by:       [EMAIL PROTECTED]
 Reported By:      raghavendra6152 at gmail dot com
-Status:           Open
+Status:           Bogus
 Bug Type:         Unknown/Other Function
 Operating System: windows xp
 PHP Version:      5.2.5
 New Comment:

Sorry, but your problem does not imply a bug in PHP itself.  For a
list of more appropriate places to ask for help using PHP, please
visit http://www.php.net/support.php as this bug system is not the
appropriate forum for asking support questions.  Due to the volume
of reports we can not explain in detail here why your report is not
a bug.  The support channels will be able to provide an explanation
for you.

Thank you for your interest in PHP.

.


Previous Comments:
------------------------------------------------------------------------

[2008-05-01 03:57:36] raghavendra6152 at gmail dot com

Description:
------------
i have installed xampp and created a my login form which i wrote a
program to access the user name and password after compile i got this
bug or error message :Parse error: syntax error, unexpected $end in C
Kindly solve this problem ....I am unable to execute this ....you can
send the solution to my mail id mentioned ...


Raghavendra 

Reproduce code:
---------------
<? session_start()?>

<html>
<head>
<title>login </title>
</head>
<body>
<h2>login</h2>
<?
        $links="<a href='main.php'>click to </a><br><br><a
href='logout.php'>click</a>";
        if($user&&$pass){
                if($logged_in_user==$user){
                        echo $user.",you are already logged in.<br><br>";
echo $links;
exit;
}
$db=mysql_connect("localhost");
mysql_select_db("raghu",$db);
$result=mysql_query("SELECT * FROM userlist WHERE name ='".$user."' AND
password= PASSWORD('".$pass."')");
if(!$result){
echo "sorry, there has ben hitch";
exit;
}
if(mysql_num_rows($result)>0){
        $logged_in_user = $user;
        session_register("logged_in_user");
        echo "welcome,".$logged_in_user.".<br><br>";
        echo $links;
        exit;
}
else
{
 echo "invalid login ,please try again<br><br>";
}

?>


<form method=post action="login.php">
Your username:
<input name="user" type=text maxlength=20 size=20>
<br>
your password:
<input name="pass" type=password maxlength=10 size=10>
<br>
<input type=submit value="login">
</body>
</html>


Expected result:
----------------
Login user and password  ...check for the user name and password if
exist,it should allow the user.If not it should say new user please
register...



------------------------------------------------------------------------


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