ID: 44952 Updated by: [EMAIL PROTECTED] Reported By: vesko at webstudiobulgaria dot com -Status: Assigned +Status: Closed Bug Type: Scripting Engine problem Operating System: Debian Lenny PHP Version: 5.3CVS-2008-05-09 (snap) Assigned To: dmitry
Previous Comments: ------------------------------------------------------------------------ [2008-05-12 09:09:59] [EMAIL PROTECTED] This bug has been fixed in CVS. Snapshots of the sources are packaged every three hours; this change will be in the next snapshot. You can grab the snapshot at http://snaps.php.net/. Thank you for the report, and for helping us make PHP better. ------------------------------------------------------------------------ [2008-05-09 08:00:45] vesko at webstudiobulgaria dot com Description: ------------ When giving variable variable argument to isset() it is not checking correctly. It was working property with the snap from 21 February (and of course works correctly with php 5.2 branch). Reproduce code: --------------- <? $var_name = 'unexisting'; if(isset($$var_name)) { print $$var_name; } ?> Expected result: ---------------- //print nothing Actual result: -------------- Notice: Undefined variable: unexisting in /home/local/test/t3.php on line 5 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=44952&edit=1
