ID: 45936
User updated by: php at bouchery dot com
Reported By: php at bouchery dot com
Status: Bogus
Bug Type: Feature/Change Request
Operating System: All
PHP Version: 5.2.6
New Comment:
To my point of view, "[]" is like an operator which mean "append the
array", but this variable is not declared.
In addition:
<?php
$x = 5;
$x[] = 7;
?>
This code will generate a "Warning: Cannot use a scalar value as an
array".
It's not possible to do that because the variable is not an array and
it show that the brackets are a kind of operator, not a simple
assignment.
Previous Comments:
------------------------------------------------------------------------
[2008-08-27 18:10:31] [EMAIL PROTECTED]
why?
You assign a new array (and its first value) to a variable. What's
wrong with that?
If you see $array[] this as:
$array = array('string');
would you expect it to fire an E_NOTICE ?
no ?
then why would this do so, if it has 100% the same meaning.
------------------------------------------------------------------------
[2008-08-27 15:30:47] php at bouchery dot com
Description:
------------
When error_reporting is set to "E_ALL" and trying append an undeclared
array, PHP should generate a "NOTICE" error.
Reproduce code:
---------------
<?php
error_reporting(E_ALL);
$array[] = 'string';
?>
Expected result:
----------------
Notice: Undefined variable: array in /var/www/script.php on line 4
Actual result:
--------------
no error.
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/?id=45936&edit=1
