ID: 47403 Updated by: scott...@php.net Reported By: jignasha_86 at yahoo dot co dot in -Status: Open +Status: Bogus Bug Type: PCRE related Operating System: All PHP Version: 5.2.9RC2 New Comment:
Sorry, but your problem does not imply a bug in PHP itself. For a list of more appropriate places to ask for help using PHP, please visit http://www.php.net/support.php as this bug system is not the appropriate forum for asking support questions. Due to the volume of reports we can not explain in detail here why your report is not a bug. The support channels will be able to provide an explanation for you. Thank you for your interest in PHP. You have a replacement back reference and that only accepts 2 numbers, $0 - $99. So $88 -> '' and hence why you see 8. If you escape the replacement correctly then it will work. Previous Comments: ------------------------------------------------------------------------ [2009-02-16 11:40:09] jignasha_86 at yahoo dot co dot in Description: ------------ In preg_replace function,you are replacing one string to other if replacing string contains $ sign in it,then preg_replace suppress $ sign and 2 charcaters after that $ sign This happens in all PHP 5 versions Reproduce code: --------------- $pattern[] = "/_BASEURL_/"; //$pattern[] = "/_BASELOGIN_/"; $pattern[] = "/_SENDERNAME_/"; $pattern[] = "/_ISSUETITLE_/"; $pattern[] = "/\'\'/"; $replacement[] = BASEURL; $replacement[] = $msg_sendername; $replacement[] = $istitle; $replacement[] = "'"; $msg_body = preg_replace($pattern, $replacement, $msg_body); if $istitle = "This is $888 ruppes"; Then It will replace it with "This is 8 rupees" ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=47403&edit=1
