ID: 49203
Updated by: [email protected]
Reported By: [email protected]
Status: Open
Bug Type: Scripting Engine problem
Operating System: Linux x86_64
PHP Version: 5.3.0
New Comment:
Ok, mysqli's contructor is not named "__construct"
Method [ <internal:mysqli, ctor> public method mysqli ] {
}
Still, one would expect that calling
call_user_func_array(array('parent', '__construct'), ...) acts the same
as parent::__construct(...) (which works). I guess somewhere the call to
__construct must be redirected to the ctor...
Previous Comments:
------------------------------------------------------------------------
[2009-08-10 07:48:18] [email protected]
The problem is not about internal classes, but classes not defining a
__construct:
class A {
}
class B extends A {
public function __construct() {
echo "here\n";
call_user_func(array('parent', '__construct'));
}
}
$x = new B;
seems like is_callable() returns true on array('parent', '__construct')
and shouldn't.
------------------------------------------------------------------------
[2009-08-10 03:57:09] [email protected]
Description:
------------
When using:
call_user_func_array(array('parent', '__construct'), $var);
This works if the parent is a user-defined class, but not if it's an
extension-provided class (the extended constructor gets called twice).
This is not easy to explain, see attached reproduce code for more
details.
My initial code was (in a class extending mysqli):
private function __construct($params) {
call_user_func_array(array('parent', '__construct'),
$params);
$this->set_charset('utf8');
}
Using this instead awfully fixes the problem:
parent::__construct($params[0], $params[1], $params[2], $params[3]);
Note that this wasn't possible in PHP 5.2.x
Warning: call_user_func_array(): First argument is expected to be a
valid callback, 'parent::__construct' was given in foo.php on line 5
Reproduce code:
---------------
<?php
class B extends mysqli {
public function __construct($var) {
echo "here\n";
call_user_func_array(array('parent', '__construct'), $var);
}
}
$x = new B(array('localhost', 'root'));
Expected result:
----------------
here
Actual result:
--------------
here
here
Warning: call_user_func_array() expects parameter 2 to be array, string
given in foo.php on line 6
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=49203&edit=1
