Edit report at http://bugs.php.net/bug.php?id=50037&edit=1
ID: 50037
Comment by: hn dot campbell at gmail dot com
Reported by: mjs at beebo dot org
Summary: No is_function() to check whether variable is an
anonymous function
Status: Bogus
Type: Feature/Change Request
Package: Feature/Change Request
Operating System: OS X
PHP Version: 5.3.0
Block user comment: N
New Comment:
Worth nothing here: as far as I can see there is no way to tell the
difference
between a Closure and a Functor (any class with an __invoke method) of
some
kind... both are objects, both are callable.
The only detectable difference I can see is that you can't create a
ReflectionFunction from a class - not a very useful test.
Previous Comments:
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[2009-10-30 16:02:31] [email protected]
Sorry, but your problem does not imply a bug in PHP itself. For a
list of more appropriate places to ask for help using PHP, please
visit http://www.php.net/support.php as this bug system is not the
appropriate forum for asking support questions. Due to the volume
of reports we can not explain in detail here why your report is not
a bug. The support channels will be able to provide an explanation
for you.
Thank you for your interest in PHP.
Use is_callable()
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[2009-10-29 21:24:42] mjs at beebo dot org
Description:
------------
There doesn't seem to be any good way to check whether a variable is a
closure/anonymous function. If
$fn = function() { };
gettype($fn) is "object", and there is no is_function() or equivalent.
The only way seems to be
gettype($fn) == "object" && get_class($fn) == "Closure"
but the anonymous function documentation says that the fact that
anonymous functions have class Closure "is an implementation detail
and should not be relied upon."
I suggest:
1. gettype() returns "function" or "closure" when passed a closure.
2. is_function() is created that returns true when passed a closure,
otherwise false.
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Edit this bug report at http://bugs.php.net/bug.php?id=50037&edit=1