Edit report at http://bugs.php.net/bug.php?id=54933&edit=1
ID: 54933
Updated by: ras...@php.net
Reported by: future_evolium at yahoo dot com
Summary: Notice: Undefined variable: dbname
-Status: Open
+Status: Bogus
Type: Bug
Package: Program Execution
Operating System: WindowsXP
PHP Version: 5.3SVN-2011-05-26 (SVN)
Block user comment: N
Private report: N
New Comment:
Your example works fine exactly as written.
Previous Comments:
------------------------------------------------------------------------
[2011-05-26 08:57:17] future_evolium at yahoo dot com
Description:
------------
I want to report a bug as soon as I installed the PHP version 5.3.5
This bug concern the function include(). For example if I have a php
file which include another php file and if I'm trying to use the
variable declared in the included file for my parent file I have the
error:
Notice: Undefined variable: dbname
Test script:
---------------
Here is my test with running parent.php
I have three files:
parent.php
<?php
include('declared.php');
$message=$dbname." should work";
echo $message;
?>
declared.php
<?php
$dbname="this script";
?>
Expected result:
----------------
I expect to recognize my variable and to print out.
this script should work
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/bug.php?id=54933&edit=1
