Edit report at https://bugs.php.net/bug.php?id=55132&edit=1
ID: 55132
User updated by: andre at webkr dot de
Reported by: andre at webkr dot de
Summary: String access to an expression gives parse error
Status: Bogus
Type: Bug
Package: Scripting Engine problem
Operating System: Windows 7
PHP Version: 5.3.6
Block user comment: N
Private report: N
New Comment:
I double-checked the manual, there it says:
"Characters within strings may be accessed and modified by specifying the
zero-based offset of the desired character after the string using square array
brackets, as in $str[42]. [...] Strings may also be accessed using braces, as
in $str{42}, for the same purpose."
The expression ((string)$i) obviously is a string, as confirmed by var_dump():
string(3) "123"
So I don't see which part of the manual you are referring to.
Previous Comments:
------------------------------------------------------------------------
[2011-07-04 19:01:44] fel...@php.net
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php
The syntax (...){..} is not intended to work.
------------------------------------------------------------------------
[2011-07-04 18:53:24] andre at webkr dot de
Description:
------------
As documented, "accessing variables of other types [...] using [] or {}
silently returns NULL". Because of this it is necessary to cast an integer to
string before string access can be done. However, this results in a parse error.
Test script:
---------------
$i = 123;
echo $i{1}; // -> empty (expected)
echo ((string)$i){1}; // -> parse error
------------------------------------------------------------------------
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Edit this bug report at https://bugs.php.net/bug.php?id=55132&edit=1
