Edit report at https://bugs.php.net/bug.php?id=60166&edit=1
ID: 60166
User updated by: np dot viktorov at gmail dot com
Reported by: np dot viktorov at gmail dot com
Summary: Locale::lookup() returns an empty string if the
first arg is an empty array
Status: Open
Type: Bug
Package: intl
Operating System: Debian GNU/Linux 6.0.2 (squeeze)
PHP Version: Irrelevant
Block user comment: N
Private report: N
New Comment:
I forgot the INTL information.
According to phpinfo() the INTL version information is this:
- version 1.1.0
- ICU version 4.4.1
Previous Comments:
------------------------------------------------------------------------
[2011-10-29 11:24:32] np dot viktorov at gmail dot com
Description:
------------
Locale::lookup() will return an empty string if the first argument is an empty
array() no matter that we have already set the default argument (argument #4)
Test script:
---------------
<?php
$available = array();
$default = "en";
$requested = "eu-us";
$result = Locale::lookup($available, $requested, null, $default);
var_dump($result);
/*
if we create atleast one element, for example "de" it will work fine
*/
Expected result:
----------------
According to the documentation we should expect to get "en" because this is the
default locale provided as the fourth argument. This doesn't happen.
Actual result:
--------------
The actual result is "" (an empty string), not null, not false, just an empty
string.
------------------------------------------------------------------------
--
Edit this bug report at https://bugs.php.net/bug.php?id=60166&edit=1
