Edit report at https://bugs.php.net/bug.php?id=40880&edit=1

 ID:                 40880
 Updated by:         paj...@php.net
 Reported by:        prometheus__0 at hotmail dot com
 Summary:            public->protected inheritance causes fatal
 Status:             Not a bug
 Type:               Bug
 Package:            Class/Object related
 Operating System:   SUSE SLES 10
 PHP Version:        5CVS-2007-03-21 (snap)
 Block user comment: N
 Private report:     N

 New Comment:

@postmaster at greg0ire dot fr

__construct applies only to the class where it is declared.

On the other hand, a method, already defined in the parent class, must be as 
visible as the one declared in the parent class and with a compatible 
signature. 
The 2nd clause is not respected in your example as the 1st argument is not 
optional. It would work if it was optional, making $a->test() possible ass it 
is 
with the parent class.

All these details are very explained in the PHP manual and other various OOP 
references out there.


Previous Comments:
------------------------------------------------------------------------
[2012-05-07 08:14:16] postmaster at greg0ire dot fr

@rasmus:
Then why is there a strict warning regarding the compatibility of method 
signatures for this code:

--------------
class Foo {
    public function test() {
    }
}
 
class Bar extends Foo {
    public function test(ArrayObject $arrayObj, $number = 0) {
        /* do stuff with $arrayObj and $number */
    }
}

---------------

and not for this one:

---------------
class Foo {
    public function __construct() {
    }
}
 
class Bar extends Foo {
    public function __construct(ArrayObject $arrayObj, $number = 0) {
        /* do stuff with $arrayObj and $number */
    }
}
------------

No, as stated here : 
- 
http://stackoverflow.com/questions/5490824/should-constructors-comply-with-the-liskov-substitution-principle
 
- and here: 
http://ralphschindler.com/2012/03/09/php-constructor-best-practices-and-the-prototype-pattern,
 the LSP does not apply to constructors for several reasons:
- When you call the constructor, you know whether you're using the type or one 
of its subtypes.
- You can't apply the LSP to an object that does not exist yet.

I think this is a design flaw. Not "massive", but a design flaw indeed.

------------------------------------------------------------------------
[2012-05-06 16:12:00] ras...@php.net

Most (all?) object oriented languages work this way. Java and C# both do. You 
can 
loosen visibility when you override a parent method, but you can never tighten 
it. This is part of what is known as the Liskov Substitution Principle and it 
is 
one of the fundamental principles of object oriented programming. You can read 
about at http://en.wikipedia.org/wiki/Liskov_substitution_principle

I can guarantee that abiding by LSP is not a bug

------------------------------------------------------------------------
[2012-05-06 15:40:26] ekincigokan at gmail dot com

Same "problem".

class A{
    public function __construct(){}
}

class B extends A {
    protected function __construct(){}
}

Please, can you tell us a reason why we can't put an private/protected access 
to B's constructor if A's constructor is public ?
Is there any logical reason to this ?


Thanks.

------------------------------------------------------------------------
[2011-09-10 22:27:24] herman dot wetherington at gmail dot com

Apparently, we don't call this a "bug" because this is not caused by a 
programming error. So I'm calling it a "massive design flaw" instead.

------------------------------------------------------------------------
[2010-10-15 23:33:35] robertoblanko at gmail dot com

Same problem here. You cannot actually apply the singleton pattern to 
subclasses with this behavior. I do not see any reason for not calling this a 
bug.

------------------------------------------------------------------------


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the rest of the comments, please view the bug report online at

    https://bugs.php.net/bug.php?id=40880


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