Edit report at https://bugs.php.net/bug.php?id=25874&edit=1
ID: 25874 Comment by: paulwolbers at home dot nl Reported by: fire at firepages dot com dot au Summary: var_export does not output valid code Status: Not a bug Type: Bug Package: Variables related Operating System: XP PHP Version: 4.3.3 Block user comment: N Private report: N New Comment: But why is the comma there? I don't want there because it looks like something's wrong (even if it's correct behaviour) by the way: you have to check your emailvalidator ... it says my emailaddress is not valid (so now i used another one) Previous Comments: ------------------------------------------------------------------------ [2003-10-14 23:04:47] il...@php.net Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php The trailing comma while unusual is perfectly valid and the code evaluates correctly. ------------------------------------------------------------------------ [2003-10-14 22:21:48] fire at firepages dot com dot au Description: ------------ output from var_export($var,true) has trailing comma so you have to strip that manually before utilising the returned string. the manual example shows this behaviour so perhaps its a feature ? Reproduce code: --------------- $yaks = array( 'dfdf'=>'a' , 'b' , 'c' , 'd' ) ; echo '$llama = ' . var_export( $yaks , true ) . ' ;' ; Expected result: ---------------- $llama = array ( 'dfdf' => 'a', 0 => 'b', 1 => 'c', 2 => 'd' ) ; Actual result: -------------- $llama = array ( 'dfdf' => 'a', 0 => 'b', 1 => 'c', 2 => 'd', ) ; ------------------------------------------------------------------------ -- Edit this bug report at https://bugs.php.net/bug.php?id=25874&edit=1
