Edit report at https://bugs.php.net/bug.php?id=54740&edit=1
ID: 54740
Updated by: m...@php.net
Reported by: dukeofgaming at gmail dot com
Summary: Ternary operator will not work with return by
reference
-Status: Open
+Status: Not a bug
Type: Bug
-Package: Compile Failure
+Package: Scripting Engine problem
PHP Version: Irrelevant
Block user comment: N
Private report: N
New Comment:
Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php
Check the second note here:
http://php.net/manual/en/language.references.return.php
Previous Comments:
------------------------------------------------------------------------
[2012-08-27 14:17:44] marrch dot caat at gmail dot com
This is a general problem with reference inside ternary operator. For ex., the
following script fails with the same error:
$link = isset($i) ? (& $arr[$i]) : null;
- while the following works fine:
$link = & $arr[$i];
------------------------------------------------------------------------
[2011-05-15 22:59:17] dukeofgaming at gmail dot com
Description:
------------
PHP fails to parse a returned by reference value when using the ternary
operator.
The test script provided illustrates a case of when it is absolutely necessary
to return by reference; if the "&" is removed then the output would be a fatal
error: "Fatal error: Cannot use [] for reading in <...>"
Test script:
---------------
$value = ($condition)?(
$some_value
):(&$object->Collection[]);
Expected result:
----------------
No errors, should be the equivalent of having:
if($condition){
$value = $some_value;
}else{
$value = &$object->Collection[];
}
Actual result:
--------------
Parse error: syntax error, unexpected '&' in <...>
------------------------------------------------------------------------
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Edit this bug report at https://bugs.php.net/bug.php?id=54740&edit=1
