ID: 21490
Updated by: [EMAIL PROTECTED]
Reported By: [EMAIL PROTECTED]
Status: Bogus
Bug Type: Unknown/Other Function
Operating System: Linux
PHP Version: 4.3.0
New Comment:
Note:
$test = ""; sets the variable test to an empty string.
So isset() will return TRUE. Since you're passing "$var" and $var is
empty, it will be set to an empty string.
That explains why it returns TRUE with "$var" and not with only $var.
Thank you for your report.
Previous Comments:
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[2003-01-07 07:58:45] [EMAIL PROTECTED]
Yes it $ddfdfdf is empty, isset will return FALSE.
According to the following script :
<?php
$test = array ('a' => 'coooool','b' => "$tests");
if (isset($test['b']) ) {
echo "OK 1! \n";
}
$test = array ('a' => 'coooool','b' => $tests);
if ( isset($test['b']) ) {
echo "OK 2! \n";
}
$tests = "lol";
$test = array ('a' => 'coooool','b' => $tests);
if ( isset($test['b']) ) {
echo "OK 3! \n";
}
?>
That returns:
OK 1!
OK 3!
If you set an element of an array to a variable that is empty, isset
will definatly return FALSE.
Excepted behaviour.
------------------------------------------------------------------------
[2003-01-07 07:53:02] [EMAIL PROTECTED]
Don't know if it's a bug or a feature... :)
$test = array ('a' => 'coooool','b' => $ddfdfdf);
if ( isset($test['b']) ) {
echo "OOOK ! \n";
}
echoes nothing, and
$test = array ('a' => 'coooool','b' => "$ddfdfdf");
if ( isset($test['b']) ) {
echo "OOOK ! \n";
}
echoes OOOK
Is this normal ?
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Edit this bug report at http://bugs.php.net/?id=21490&edit=1
