ID: 22892
Updated by: [EMAIL PROTECTED]
Reported By: jorgen at webstores dot nl
-Status: Open
+Status: Bogus
Bug Type: Unknown/Other Function
Operating System: Windows XP
PHP Version: 4.3.2RC1
New Comment:
Your have mistaken two different meanings of [] operator which can mean
both string offset (as is in your example) and array.
For this reason the use of [] has been discouraged for some time and {}
has been introduced as the replacement for the case of accessing string
characters.
Previous Comments:
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[2003-03-26 04:34:54] jorgen at webstores dot nl
<?php
$var = 'ABC';
echo ($var[0]); // Displays 'A'
echo ($var[1]); // Displays 'B'
echo ($var[2]); // Displays 'C'
echo join(" ", $var); // Wont work
?>
Do you get my point? One can call a 'string' variable as an Array, but
one can not use that same 'string' as an Array parameter. Seems a
little bit odd to me...
Because I want to display: 'ABC' as 'A B C', would this be very handy.
Kind regards,
Jorgen Horstink
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Edit this bug report at http://bugs.php.net/?id=22892&edit=1
