ID: 23859
Updated by: [EMAIL PROTECTED]
Reported By: csnyder at chxo dot com
-Status: Open
+Status: Wont fix
Bug Type: Feature/Change Request
Operating System: Linux / FreeBSD
PHP Version: 4.3.1
New Comment:
Changing this would break backwards compatibility.
And btw. this is much more intuitive:
#!/usr/local/bin/php
<?php
$options = getopt("abcdef");
if (isset($options['e'])) print "I took e!";
?>
Previous Comments:
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[2003-05-28 10:45:07] csnyder at chxo dot com
The current behavior of getopts() is counter-intuitive.
>From the manual:
"If an option does not have an argument, the value will be set to
FALSE."
But this leads to a script like the following:
#!/usr/local/bin/php
<?
$options = getopt("abcdef");
if ($options['e']===FALSE) print "I took e!";
?>
This is confusing -- we test for the presence of an option in the
command line by checking whether it is FALSE?
It would be quite helpful, at least in cases where no additional value
was expected (an option string of "a" vs. an option string of "a:") for
getopts to set the value to TRUE. The script above could then be:
#!/usr/local/bin/php
<?
$options = getopt("abcdef");
if ($options['e']) print "I took e!";
?>
...which is much easier to figure out.
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Edit this bug report at http://bugs.php.net/?id=23859&edit=1
