ID: 25503 Updated by: [EMAIL PROTECTED] Reported By: o_gangrel at hotmail dot com Status: Bogus Bug Type: SQLite related Operating System: Windows 98 PHP Version: 5.0.0b1 (beta1) New Comment:
The parameter type checking is performed before the query is executed; PHP always returns NULL in this case, as it does for a very large number of other functions. Just fix your script to use !$sqlite_connection and get over it :) Previous Comments: ------------------------------------------------------------------------ [2003-09-11 20:32:12] o_gangrel at hotmail dot com >From the http://www.php.net/sqlite_query "Regardless of the query type, this function will return FALSE if the query failed." Return NULL is a wrong return value. ------------------------------------------------------------------------ [2003-09-11 20:07:04] [EMAIL PROTECTED] Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php You gave a function the wrong arguments; PHP will return NULL in this case. So this is not a bug in PHP, but in your script for not checking error returns correctly. ------------------------------------------------------------------------ [2003-09-11 19:08:39] o_gangrel at hotmail dot com Description: ------------ I am using the configuration Apache/2.0.43 (Win32) PHP/5.0.0b1 with PHP as a module of Apache. When I make a query on a SQLite database with a not valid SQL query, the the sqlite_query() produces an Warning, that's ok. But when the script continues the SQLite_fetch_array() returns a NULL and it is expected to return a FALSE. The Warning message produced by the SQLite_fetch_array() is right, but the return value is not expected. I found solutions to not hapen this erro, but this is not expected. And I'm sorry, I didn't tested the CVS version and other vertion of the Apache. Reproduce code: --------------- $query1 = "SELECT * FROM sqlite_master"; $query2 = "foobar"; $db_file = "test.db"; $sqlite_connection = sqlite_open($db_file, 0666, $sqlite_error); if($sqlite_connection === false) { die($sqlite_error); } $result = sqlite_query($sqlite_connection, $query1); echo var_dump(sqlite_fetch_array($result, SQLITE_BOTH))."\n"; $result = sqlite_query($sqlite_connection, $query2); echo var_dump(sqlite_fetch_array($result, SQLITE_BOTH))."\n"; sqlite_close($sqlite_connection); Expected result: ---------------- array(10) { [0]=> string(5) "table" ["type"]=> string(5) "table" [1]=> string(4) "test" ["name"]=> string(4) "test" [2]=> string(4) "test" ["tbl_name"]=> string(4) "test" [3]=> string(1) "3" ["rootpage"]=> string(1) "3" [4]=> string(24) "CREATE TABLE test (test)" ["sql"]=> string(24) "CREATE TABLE test (test)" } bool(false) Actual result: -------------- array(10) { [0]=> string(5) "table" ["type"]=> string(5) "table" [1]=> string(4) "test" ["name"]=> string(4) "test" [2]=> string(4) "test" ["tbl_name"]=> string(4) "test" [3]=> string(1) "3" ["rootpage"]=> string(1) "3" [4]=> string(24) "CREATE TABLE test (test)" ["sql"]=> string(24) "CREATE TABLE test (test)" } Warning: sqlite_query(): near "foobar": syntax error in D:\internet\pages\sqlite\bugscript.php on line 16 Warning: sqlite_fetch_array() expects parameter 1 to be resource, boolean given in D:\internet\pages\sqlite\bugscript.php on line 17 NULL ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=25503&edit=1
