ID: 26054 User updated by: sascha dot wildgrube at steganos dot com Reported By: sascha dot wildgrube at steganos dot com Status: Open Bug Type: *Programming Data Structures Operating System: all PHP Version: 4.3.2 New Comment:
An even better solution would be the need to initialize variables like that "var $nValue;". This way even typos in in lvalues would not do any harm. We once observed how much percent of the time was consumed by this bug. We found out that 30% of the time when working on php code could be saved if php had strict variable usage. Previous Comments: ------------------------------------------------------------------------ [2003-10-31 07:26:30] sascha dot wildgrube at steganos dot com Description: ------------ Any variable identifier can be used in a statement - even if it hasn't been referenced before - without producing an error. Most of the time when debuggong php code is spent for searching typos in variable names. I consider it a bug that php does not produce and display error if it encounters an unreferenced variable in a statement. A solution could be a "strict" statement. That tells php to throw errors in that case to stay backward compatible. An even better solution would be the need to Reproduce code: --------------- $nValue1 = 10; $nValue2 = 20; print($nVale1 + $nValue2); Expected result: ---------------- Expected: 30 No, it is: 20 Why, because of the typo in line 3. What I want to happen in that case is this: Parse error: parse error in /somefile.php4 on line 3: unreferenced object "$nVale1" Actual result: -------------- 20 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=26054&edit=1
