ID: 26980 Updated by: [EMAIL PROTECTED] Reported By: reklov at unitedklasens dot de -Status: Open +Status: Bogus Bug Type: Arrays related Operating System: Win98SE PHP Version: 4.3.4 New Comment:
Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php {} can be used to denoted array or string indices. You would need this: ${var${i}} Nothe that the second '{' here is after the second '$' not before as in your code. The notation should force the compiler to generate code that concatenates the string var with the result of variable $i and use that as a variable name. This is neither possible nor planned. You need to evaluate the value of the mentioned concatentaion yourself. Previous Comments: ------------------------------------------------------------------------ [2004-01-20 12:43:42] reklov at unitedklasens dot de Description: ------------ With $var{$i} = 'Test' I wanted to create a variable with the name 'var1', using the '{}' and $i == 1, like ${$a} (http://www.php.net/manual/en/language.variables.variable.php) Insted of this, it will create an array, as if I had used '[]' instead of '{}'. Reproduce code: --------------- <?php $i = 1; $var{$i} = 'Test'; echo $var{$i}; echo '<br>'; echo $var{1}; echo '<br>'; echo $var1; ?> Expected result: ---------------- Test<br> Test<br> //not sure, what would happen... Test Actual result: -------------- Test<br> Test<br> ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=26980&edit=1
