ID: 27401 Updated by: [EMAIL PROTECTED] Reported By: ycallen at ndsisrael dot com Status: Bogus Bug Type: Apache related Operating System: RHEL linux PHP Version: 4.3.4 New Comment:
You're using old version too. Latest stable CVS snapshot has lot of bugs fixed.. Previous Comments: ------------------------------------------------------------------------ [2004-02-26 07:22:43] ycallen at ndsisrael dot com If that was the case then no php scripts would work at all.Basic php scripts work.The only problem i found so far was with fopen. ------------------------------------------------------------------------ [2004-02-26 07:17:07] [EMAIL PROTECTED] Of course it times out in debug mode since there's only one child serving requests..and the one request is taken by your script calling the other script.. ------------------------------------------------------------------------ [2004-02-26 06:14:44] ycallen at ndsisrael dot com it works using : wget -O - "http://localhost/~php/recieve.php?param1=1¶m2=2" ------------------------------------------------------------------------ [2004-02-26 06:07:44] postings-php-bug at hans-spath dot de What happens when you execute the following line on a shell? wget -O - "http://localhost/~php/recieve.php?param1=1¶m2=2" ------------------------------------------------------------------------ [2004-02-26 05:57:54] ycallen at ndsisrael dot com Description: ------------ I do the following steps: 1.I run apache in debug mode(httpd -X). 2.I have a php script(send.php) that tries to access another php script(recieve.php)using fopen with a url.The url points to localhost[example : fopen("http://localhost/~php/recieve.php)]. 3.The program hangs and eventually times out with the following warning : "Warning: fopen(http://localhost/~php/recieve.php?param1=1m2=2): failed to open stream: HTTP request failed! ^ in /home/php/public_html/send.php on line 6" This only happens when i run apache in debug mode.When i run apache in regular mode then it works. Reproduce code: --------------- recieve.php: <?php echo "with GET<br>"; echo "my first param is: ".$_GET['param1']."<br>"; echo "my second param is: ".$_GET['param2']."<br>"; ?> send.php: <?php $url = "http://localhost/~php/recieve.php?param1=1¶m2=2"; $opts = array('http' => array('method' => "GET")); $context = stream_context_create($opts); echo "before fopen<br>"; $fp = fopen($url, "r", true, $context); fpassthru($fp); fclose($fp); ?> Expected result: ---------------- before fopen with GET my first param is: 1 my second param is: 2 Actual result: -------------- before fopen Warning: fopen(http://localhost/~php/recieve.php?param1=1m2=2): failed to open stream: HTTP request failed! ^ in /home/php/public_html/send.php on line 6 Warning: fpassthru(): supplied argument is not a valid stream resource in /home/php/public_html/send.php on line 7 Warning: fclose(): supplied argument is not a valid stream resource in /home/php/public_html/send.php on line 8 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=27401&edit=1