ID:               10088
 Comment by:       nude-preteen1561 at hotmail dot com
 Reported By:      admin at room41 dot net
 Status:           Closed
 Bug Type:         Class/Object related
 Operating System: W2K
 PHP Version:      4.0.4pl1
 New Comment:

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Previous Comments:
------------------------------------------------------------------------

[2001-11-17 12:46:18] [EMAIL PROTECTED]

Your example is wrong. You're copying object everywhere like it is
christmas day.

Here's the corrected example for your convenience:
<?
$d1 = &new obj("one");  //      Suppress the warning over the missing
argument
$d2 = &new obj("two",   $d1);
$d3 = &new obj("three", $d2);
$d4 = &new obj("four",  $d3);
$d5 = &new obj("five",  $d4);

// Dump what should be the entire linked list
$d1->dump();
print("\n\n");

// Now to demonstrate the problem:
// No matter where you begin the dump() from, only the
// $this node and its immediate successor are printed.
$d2->dump(); print("\n\n");
$d3->dump(); print("\n\n");

class obj {
  var $next;
  var $name;
        
  function &obj($name,&$prev) {
    //  Add each new object as the "next" pointer of the preceeding one

    $this->name = $name;
    if ($prev) $prev->next = &$this;
  }
function dump() {
  for ( $ptr = &$this; $ptr; $ptr = &$ptr->next) print($ptr->name .
"\n");
  }
}
?>

Even if this example uses '&' where not needed it's good that way
because not even a single object gets copied by accident.

Closed.

------------------------------------------------------------------------

[2001-03-31 04:58:18] admin at room41 dot net

The script shown attempts to implement a linked list, but the problem
is more general and occurs in many similar situations.

<?
$d1 = @new obj("one");  //      Suppress the warning over the missing
argument
$d2 = new obj("two",   $d1);
$d3 = new obj("three", $d2);
$d4 = new obj("four",  $d3);
$d5 = new obj("five",  $d4);

// Dump what should be the entire linked list
$d1->dump();
print("<p>");

// Now to demonstrate the problem:
// No matter where you begin the dump() from, only the
// $this node and its immediate successor are printed.
$d2->dump(); print("<p>");
$d3->dump(); print("<p>");

class obj {
  var $next;
  var $name;
        
  function &obj($name,&$prev) {
    //  Add each new object as the "next" pointer of the preceeding one

    this->name = $name;
    if ($prev) $prev->next = $this;
  }
function dump() {
  for ( $ptr = $this; $ptr; $ptr = $ptr->next) print($ptr->name .
"<br>");
  }
}
?>

It seems that when an object's data is manipulated by a different
object - even as here, of the same class - the changes made to the
object are lost when its context expires.

Configuration: Absolutely standard
Webserver: Apache and IIS ... same problem in both, and under cgi and
as a module
Aggravation factor: Immense

Cheer chaps for an otherwise excellent language!


------------------------------------------------------------------------


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