ID: 29582
User updated by: mydwin at msn dot com
-Summary: The Bug on if()
Reported By: mydwin at msn dot com
Status: Open
Bug Type: MySQL related
Operating System: Windows 2003 Enterprise
PHP Version: 5.0.0
New Comment:
By the Way.
We can't use this
$Temp_From=$DB->query( "SELECT * FROM test WHERE id=$iFromID"
)->fetch_assoc()[0];
but we can use it in this way
$Temp_From=$DB->query( "SELECT * FROM test WHERE id=$iFromID"
)->fetch_assoc();
$Temp_From=$Temp_From[0];
Previous Comments:
------------------------------------------------------------------------
[2004-08-09 08:43:17] mydwin at msn dot com
Description:
------------
-= The SQL is =-
CREATE TABLE `test` (
`id` int(10) unsigned NOT NULL auto_increment,
`Name` varchar(50) collate utf8_bin NOT NULL default '',
PRIMARY KEY (`id`)
) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_bin AUTO_INCREMENT=5
;
INSERT INTO `test` VALUES (1, 0x61);
INSERT INTO `test` VALUES (2, 0x62);
INSERT INTO `test` VALUES (3, 0x63);
INSERT INTO `test` VALUES (4, 0x64);
-= the test.php code is =-
<pre><?php
$iFromID = $_POST["FromID"]|0;
$iToID = $_POST["ToID"]|0;
$DB = new mysqli( "localhost", "root", "", "testDB" );
if( $Temp_From=$DB->query( "SELECT * FROM test WHERE id=$iFromID"
)->fetch_assoc() && $Temp_To=$DB->query( "SELECT * FROM test WHERE
id=$iToID" )->fetch_object() )
{
print_r($Temp_From);
echo "\n\n\n";
print_r($Temp_To);
}
?>
<form method="post" action="test.php">
<input name="FromID" value="1" /> <input name="ToID" value="2" />
<input type="submit" value="Submit" /> <input type="reset"
value="Reset" />
</form>
</pre>
Expected result:
----------------
Array
(
[id] => 1
[Name] => a
)
stdClass Object
(
[id] => 2
[Name] => b
)
Actual result:
--------------
1
stdClass Object
(
[id] => 2
[Name] => b
)
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=29582&edit=1
