ID: 31229
Updated by: [EMAIL PROTECTED]
Reported By: douglasrice at yahoo dot com
-Status: Open
+Status: Bogus
Bug Type: Apache related
Operating System: Windows XP Pro
PHP Version: 4.3.10
New Comment:
The output seems to be correct for a PNG image, it seems that the
header identifying the content is being removed by apache or ignored by
your browser.
Previous Comments:
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[2004-12-21 13:40:16] douglasrice at yahoo dot com
Description:
------------
Apologies if this isn't a bug. Suspect it is an Apache problem.
I have Apache 1.3.33 and PHP 4.3.10 running on Windows XP Pro with
Service Pack 2 installed.
I have retrieved a jpeg file into a php variable. When trying to
display the image i.e. echo("$pic"), the data of the jpeg rather than
the jpeg itself is printed out. Have used the sample code for
"Creating a new GD image stream and outputting an image." in php manual
and this does the same thing...display the image "data" rather than the
image. I have included header info ie content type = image/png or
image/jpeg to with no luck.
I suspect it is a setting in Apache, but have trawled the internet and
found many people with the same problem, but no-one has an
answer.....can you help?
Reproduce code:
---------------
<?php
header("Content-type: image/png");
$im = @imagecreate(100, 50)
or die("Cannot Initialize new GD image stream");
$background_color = imagecolorallocate($im, 255, 255, 255);
$text_color = imagecolorallocate($im, 233, 14, 91);
imagestring($im, 1, 5, 5, "A Simple Text String", $text_color);
imagepng($im);
imagedestroy($im);
?>
Expected result:
----------------
An image is drawn to screen
Actual result:
--------------
The following is displayed to screen...
PNG IHDRd2PLTE[˝eIDATxc` `fx`
[vK \6p)u.``iP o9٦©Ty܍㥀X&Zu
Y IENDB`
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