ID: 31529 User updated by: david at 21stcd dot com Reported By: david at 21stcd dot com Status: Bogus Bug Type: Scripting Engine problem Operating System: windows xp PHP Version: 4.3.8 New Comment:
even so "\x".$hex will not work either. It was my understanding you could subsitiute vars into strings using the previous method I outline, where as the on I just outlined add the vars value onto the end of the string. Previous Comments: ------------------------------------------------------------------------ [2005-01-14 04:46:53] [EMAIL PROTECTED] \x$ is not valid syntax. ------------------------------------------------------------------------ [2005-01-13 10:08:58] david at 21stcd dot com Description: ------------ The problem comes from the use of var substitution or addtion to strings that you are trying to "escape" I find this problem when trying to create escaped hex strings to write data to sockets. Reproduce code: --------------- <?PHP $hex = "FF"; echo "\x$hex"; ?> Expected result: ---------------- ÿ Actual result: -------------- \xFF ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=31529&edit=1
