ID: 33466
Updated by: [EMAIL PROTECTED]
Reported By: clynx at succont dot de
-Status: Open
+Status: Bogus
Bug Type: Scripting Engine problem
Operating System: FreeBSD 4.10/FreeBSD 5.4/WinXP
PHP Version: 5CVS-2005-06-24 (dev)
New Comment:
array_shift() accepts only variables passed by reference.
Obviously an expression result is not a variable.
Previous Comments:
------------------------------------------------------------------------
[2005-06-24 15:18:58] clynx at succont dot de
Description:
------------
When you try to use array_intersect in combination with a different
Function, it leads to a strange Error Message.
The Reproduce Code give the Error while the following does not:
<?php
$array1 = array('foo', 'bar', 'test');
$array2 = array('foo', 'me' );
$result = array_intersect( $array1, $array2 );
var_dump( array_shift( $result ) );
?>
And as far as array_intersect retuns an Array (a Variable ;o) this
Error is a little bit strange.
Reproduce code:
---------------
<?php
$array1 = array('foo', 'bar', 'test');
$array2 = array('foo', 'me' );
var_dump( array_shift( array_intersect( $array1, $array2 ) ) );
?>
Expected result:
----------------
webdev# php /htdocs/beta.webdev/succont.Unitized/test.php
string(3) "foo"
Actual result:
--------------
webdev# php /htdocs/beta.webdev/succont.Unitized/test.php
PHP Fatal error: Only variables can be passed by reference in
/usr/local/htdocs/beta.webdev/succont.Unitized/test.php on line 4
------------------------------------------------------------------------
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Edit this bug report at http://bugs.php.net/?id=33466&edit=1
