ID:               34553
 Updated by:       [EMAIL PROTECTED]
 Reported By:      webdev at concraption dot com
-Status:           Open
+Status:           Bogus
 Bug Type:         *Network Functions
 Operating System: Windows 2000/XP
 PHP Version:      5.0.5
 New Comment:

.


Previous Comments:
------------------------------------------------------------------------

[2005-09-19 22:29:16] webdev at concraption dot com

I reinstalled PHP and now var_dump returns bool(false), so it must've
been something with that installation. Thanks for your help.

------------------------------------------------------------------------

[2005-09-19 22:25:01] [EMAIL PROTECTED]

Your code doesn't really depend on what the return value is, as ("" ==
false) in PHP. So if you get the error you get, $hosts is neither empty
string, nor false. 
And I can't reproduce it, btw.
So please come up with the real code.

------------------------------------------------------------------------

[2005-09-19 22:03:14] webdev at concraption dot com

string(0) ""

------------------------------------------------------------------------

[2005-09-19 21:44:02] [EMAIL PROTECTED]

what do you get with this:
<?php
...
var_dump(gethostbynamel($hostname));
...
?>

?

------------------------------------------------------------------------

[2005-09-19 21:39:58] webdev at concraption dot com

Description:
------------
The online documentation for gethostbynamel() states that if the lookup
fails, it will return FALSE. The Win32 binary of PHP 5.0.5 returns what
appears to be an empty string, rather than FALSE on the case of failed
lookup. If this is an error in the documentation, I apologize for your
time.

I was able to devise a workaround using is_array() in an IF block, but
out of curiousity I added die(">".$hosts."<"); and PHP returned ><,
which leads me to believe that when the lookup fails, $hosts is an
empty string rather than FALSE.

Reproduce code:
---------------
<?
$hosts = gethostbynamel($hostname);
if ($hosts != FALSE) {
     echo $hostname." is tied to the following IPs:<br><br>";
     foreach ($hosts as $ip) {
          echo "IP: ".$ip."<br>";
     }
} else {
     echo $hostname." is not tied to any IP.";
}

Expected result:
----------------
$hostname is tied to the following IPs:

IP: first_ip
IP: second_ip

etc...

OR

$hostname is not tied to any IP.

Actual result:
--------------
Warning: Invalid argument supplied for foreach() in
C:\Server\sites\apps\iptools.php on line 12


------------------------------------------------------------------------


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