ID: 35004
User updated by: jmcentire at jackhenry dot com
Reported By: jmcentire at jackhenry dot com
-Status: Closed
+Status: Bogus
Bug Type: Variables related
Operating System: Windows server 2003
PHP Version: 5.0.5
New Comment:
Changed to "bogus"
Previous Comments:
------------------------------------------------------------------------
[2005-10-27 22:43:00] jmcentire at jackhenry dot com
Sorry - this appears to be a problem only under MediaWiki. When ran in
a test.php by itself:
<?php
var_dump($_SERVER["AUTH_USER"]);
?>
returns the correct value with the seperator. I'll close this and
pursue this with mediawiki.
------------------------------------------------------------------------
[2005-10-27 22:26:46] [EMAIL PROTECTED]
Thank you for this bug report. To properly diagnose the problem, we
need a short but complete example script to be able to reproduce
this bug ourselves.
A proper reproducing script starts with <?php and ends with ?>,
is max. 10-20 lines long and does not require any external
resources such as databases, etc.
If possible, make the script source available online and provide
an URL to it here. Try to avoid embedding huge scripts into the report.
------------------------------------------------------------------------
[2005-10-27 22:20:48] jmcentire at jackhenry dot com
>> var_dump($_SERVER["AUTH_USER"]);
prints
string(13) "DDDDDDuuuuuuu"
where DDDDDD is the 6 character domain name
and uuuuuuu is the 7 character user name
No seperator
------------------------------------------------------------------------
[2005-10-27 21:44:00] [EMAIL PROTECTED]
what does this code print:
var_dump($_SERVER["AUTH_USER"]);
?
------------------------------------------------------------------------
[2005-10-27 21:40:39] jmcentire at jackhenry dot com
Description:
------------
php_info() shows server variable AUTH_USER in correct format:
DOMAIN\username
However, the $_server["AUTH_USER"] in code returns "DOMAINusername" (no
seperator).
Reproduce code:
---------------
list($domain,$username) = split('[\]',$_SERVER["AUTH_USER"],2);
print "Domain: $domain UserName: $username";
Expected result:
----------------
Domain: DOMAIN UserName: username
Actual result:
--------------
Domain: DOMAINusername UserName:
------------------------------------------------------------------------
--
Edit this bug report at http://bugs.php.net/?id=35004&edit=1
