ID:               36405
 Updated by:       [EMAIL PROTECTED]
 Reported By:      thom at genx dot net
-Status:           Open
+Status:           Bogus
 Bug Type:         Scripting Engine problem
 Operating System: Linux (gentoo)
 PHP Version:      5.1.2
 New Comment:

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

$x = 'foo' is an expression and cannot be passed by reference. Enable
E_STRICT to see the message.


Previous Comments:
------------------------------------------------------------------------

[2006-02-16 00:33:18] thom at genx dot net

Description:
------------
Inline assignment of a variable used as an argument to a function
(passed by reference) does not behave properly.  Earlier versions of
PHP (< 5.1.2) and other programming languages recognize the assignment
before the function call is made.  It seems that PHP 5.1.2 recognizes
the assignment after the function call is made.

Reproduce code:
---------------
<?php
function testAppend(&$string)
{
        $string .= 'testAppend';
}

testAppend($x = 'foo');
echo $x;
?>


Expected result:
----------------
footestAppend

Actual result:
--------------
foo


------------------------------------------------------------------------


-- 
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