ID:               36682
 User updated by:  daniele_dll at yahoo dot it
 Reported By:      daniele_dll at yahoo dot it
 Status:           Bogus
 Bug Type:         Scripting Engine problem
 Operating System: Windows XP SP2
 PHP Version:      5.1.2
 New Comment:

This doesn't make sense!

Why an heredoc needs, to works correctly, a line only for it, without
other stuff after the terminator (with a semicolon)?
If there is a terminator and an ending semicolon, the command
terminates there, so i should add other commands in the same line
without problems.

I don't think this is a "really" bug, but it is a "logical" bug.

If the heredoc terminator is founded and there is a semicolon to
terminate the line, a new command can be executed, like all other
structures in php.

i can write
<?php
$a = 1; $c = 'daniele_dll'; $b = 'test'; $a = $b; $b = $c; echo $a . $b
. $c; echo print_r($_SERVER, true); die("ASD");
?>

without problems, so have heredoc that doesn't let to me to  add
multiple commands after the heredoc termination (plus semicolon)
doesn't make sense for me.

There is a particular reason to manage heredoc in this way?


Previous Comments:
------------------------------------------------------------------------

[2006-03-10 18:07:34] [EMAIL PROTECTED]

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

The terminating new line is obligatory

------------------------------------------------------------------------

[2006-03-10 17:50:07] daniele_dll at yahoo dot it

Description:
------------
Terminating an heredoc without a newline cause a parse error.

The reported code was tested with php 5.0.4, 5.0.5 and 5.1.2

Reproduce code:
---------------
<?php
echo <<< HEREDOC_EOF

Test
Heredoc

All works fine!

HEREDOC_EOF;?>

Expected result:
----------------
This code should output the text into the heredoc

Actual result:
--------------
The execution of this code return a parse error


------------------------------------------------------------------------


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