ID: 37270 Updated by: [EMAIL PROTECTED] Reported By: lacak at users dot sourceforge dot net Status: Bogus Bug Type: *General Issues Operating System: Windows 98 PHP Version: 5.1.3 New Comment:
It will cause memory corruptions. Yes, I know it's unfortunate, but ATM it's not fixable. Previous Comments: ------------------------------------------------------------------------ [2006-05-03 05:23:51] lacak at users dot sourceforge dot net Yes I understand, that $v=0 in f($v=0) is expression in POV of php, but in POV of user it is : 1. initializing variable 2. passing this variable as by reference argument to function And second, why this produces no error message (no warning, no notice; error_reporting=E_ALL) under 4.4.2 and works it as expected ? This seems to me like regression problem between 4.4 -> 5.1 ? ------------------------------------------------------------------------ [2006-05-02 07:10:33] [EMAIL PROTECTED] Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php Turn on error displaying and you'll see "only variables can be passed by reference". "$v=..." as function argument is an expression. Please use a support channel in future. ------------------------------------------------------------------------ [2006-05-02 06:43:38] lacak at users dot sourceforge dot net Description: ------------ See please the php reproduce code. In PHP 4.4.2 returns "Expected result" In PHP 5.1.3 returns "Actual result" Reproduce code: --------------- <?php function a(&$p) { $p=array("a"=>"1", "b"=>2); } function b(&$p) { $p=1; } a($v1=array()); print_r($v1); b($v2=0); var_dump($v2); ?> Expected result: ---------------- Array ( [a] => 1 [b] => 2 ) int(1) Actual result: -------------- Array ( ) int(0) ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=37270&edit=1
