ID: 37854 Updated by: [EMAIL PROTECTED] Reported By: spam at codeword dot net -Status: Open +Status: Bogus Bug Type: Class/Object related -Operating System: Win XP +Operating System: * -PHP Version: 5.1.4 +PHP Version: * New Comment:
Thank you for taking the time to write to us, but this is not a bug. Please double-check the documentation available at http://www.php.net/manual/ and the instructions on how to report a bug at http://bugs.php.net/how-to-report.php First we don't allow changesin the typhints in derived classes/implementing classes. Second you need to learn inheritance rules again. Your code would break is-a relation. Previous Comments: ------------------------------------------------------------------------ [2006-06-19 22:11:34] spam at codeword dot net Description: ------------ When adding type hinting to an interface then implementing that interface using a derived class, the script compiler does not seem to recognise that the implemented type hint is derived from the interfaces type hint. I hope that makes sense. The code below may be more clear. Reproduce code: --------------- <?php interface MyInterface{public function test(ClassA $object);} class MyClass implements myInterface{ public function test(ClassB $object){// should work but does not echo $object->x; } } class ClassA {public$x = "Class is ClassA"; } class ClassB extends ClassA{ public $x = "Class is ClassB";} $myclass = new MyClass; $a = new ClassA; $b = new ClassB; $myclass->test($b); $myclass->test($a); ?> Expected result: ---------------- Class is ClassB Fatal error: Argument 1 passed to MyClass::test() must be an instance of ClassB, called in typeHintTest.php on line 14 and defined in typeHintTest.php on line 4 Actual result: -------------- Fatal error: Declaration of MyClass::test() must be compatible with that of MyInterface::test() in typeHintTest.php on line 3 ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=37854&edit=1
