ID:               38018
 Updated by:       [EMAIL PROTECTED]
 Reported By:      php dot bugs at login dot hedim dot ch
-Status:           Open
+Status:           Bogus
 Bug Type:         Class/Object related
 Operating System: irrelevant
 PHP Version:      5.1.4
 New Comment:

Ok, let me explain how it works:
1) we got a serialized object.
2) unserialize() creates an object #2.
3) unserialize() looks for __wakeup() function and calls it.
4) exception is thrown.
5) unserialize() fails and destroys it's result value (to prevent
memory leak) - here is where __destruct() for object #2 is called.
6) engine detects an unhandled exception and exit()'s.
All of this is expected and I don't see any bugs here.


Previous Comments:
------------------------------------------------------------------------

[2006-07-06 00:40:41] php dot bugs at login dot hedim dot ch

Thank you for your response.

While I admit that the code example I gave was confusing, I believe it
is not bogus. It is true that there is only one call to __destruct with
the changed code, but it's the wrong one. The correct call to __destruct
has disappeared for a different reason.

This is what happens with the changed code: Because the Foo instance #1
is assigned to $var, it would only be destructed when $var goes out of
scope or (as in this case) when the script terminates (normally).

When unserializing $str, __wakeup is called on the unserialized Foo
instance #2 and throws an exception. Then, __destruct is called on Foo
instance #2. This is imho wrong because Foo instance #2 doesn't really
exist. The exception indicates it could not be reconstructed, just like
an exception from __construct does. If Foo instance #2 doesn't really
exists, there is nothing to destruct and __destruct should not be
called.

The correct call to __destruct on Foo instance #1 doesn't happen
anymore because the above exception terminates the script with a fatal
error. Wrapping a try { } around the unserialize would bring the call
to Foo #1's __destruct back.

To prove this, I have extended the reproduce code (see below) to also
print out which object is destructed.

The point is this: If __destruct is not called for objects that throw
an exception from __construct, then it should not be called either for
those that throw an exception from __wakeup. In both cases, the object
"could not be (re-) constructed", therefore there is nothing to
destruct.

I hope this makes things clearer and I apologize for the confusing
description and code example before.

Thank you for looking into this matter again.

Extended reproduce code:
------------------------
class Foo
{
    function __wakeup()
    {
        throw new Exception;
    }

    function __destruct()
    {
        echo "hello from $this's destructor\n";
    }
}

$var = new Foo;
echo "$var\n";
$str = serialize($var);
unserialize($str);

Expected result:
----------------
Object id #1
Fatal error: Uncaught exception 'Exception' [...]
No output from any destructor. The exception terminates the script
before any object can be destructed.

Actual result:
--------------
Object id #1
hello from Object id #2's destructor
Fatal error: Uncaught exception 'Exception' [...]

------------------------------------------------------------------------

[2006-07-05 21:36:24] [EMAIL PROTECTED]

Change your code to this:

$var = new Foo;
$str = serialize($var);
unserialize($str);

and voila - no second destructor call.
The first destructor is called for the temporary var.

------------------------------------------------------------------------

[2006-07-05 20:31:32] php dot bugs at login dot hedim dot ch

Description:
------------
If __wakeup threw an exception when unserializing an object, __destruct
is called on that object. For the same reasons as __destruct is not
called if __construct threw an exception (see bug #29368), it should
not be called here either.

Reproduce code:
---------------
class Foo
{
    function __wakeup()
    {
        throw new Exception;
    }

    function __destruct()
    {
        echo "hello from destructor\n";
    }
}

unserialize(serialize(new Foo));


Expected result:
----------------
hello from destructor (from the destructor of the object to be
serialized)

Actual result:
--------------
hello from destructor (from the destructor of the object to be
serialized)
hello from destructor (from the destructor of the object that fails to
unserialize)


------------------------------------------------------------------------


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