ID: 38215 Updated by: [EMAIL PROTECTED] Reported By: php at elitecoders dot com -Status: Open +Status: Wont fix Bug Type: Scripting Engine problem Operating System: CentOS PHP Version: 4.4.2 New Comment:
Parse error: syntax error, unexpected '=', expecting ')' You have to update your PHP version if you want to use this syntax. Previous Comments: ------------------------------------------------------------------------ [2006-07-26 05:32:29] php at elitecoders dot com Description: ------------ When a function argument list contains a variable reference which has a default value, there is no output. It may be because of a crash, but I was unable to test for that because I don't have access to the log files. This reproduce code works as expected in php 5. Reproduce code: --------------- <?php function exec_bug(&$var_ref = NULL) { } echo "working."; ?> Expected result: ---------------- working. ------------------------------------------------------------------------ -- Edit this bug report at http://bugs.php.net/?id=38215&edit=1