ID:               38215
 Updated by:       [EMAIL PROTECTED]
 Reported By:      php at elitecoders dot com
-Status:           Open
+Status:           Wont fix
 Bug Type:         Scripting Engine problem
 Operating System: CentOS
 PHP Version:      4.4.2
 New Comment:

Parse error: syntax error, unexpected '=', expecting ')'
You have to update your PHP version if you want to use this syntax.


Previous Comments:
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[2006-07-26 05:32:29] php at elitecoders dot com

Description:
------------
When a function argument list contains a variable reference 
which has a default value, there is no output. It may be 
because of a crash, but I was unable to test for that because 
I don't have access to the log files.

This reproduce code works as expected in php 5.

Reproduce code:
---------------
<?php

function exec_bug(&$var_ref = NULL) {


}

echo "working.";

?>

Expected result:
----------------
working.



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