ID:               38788
 Updated by:       [EMAIL PROTECTED]
 Reported By:      j dot henge-ernst at interexa dot de
-Status:           Open
+Status:           Bogus
 Bug Type:         Scripting Engine problem
 Operating System: linux
 PHP Version:      5.1.6
-Assigned To:      
+Assigned To:      dmitry
 New Comment:

This is not a BUG, but expected behavior.
look into your __clone() method. $this->a['f'] and $this->b are
references to the same variable (to $x1->b). You destroy $this->a['f'],
but not $this->b that still point ot $x1->b, and makes $this->a['f']
reference to the same var again.

You would probably like change your code to:

public function __clone() { unset($this->b); $this->a['f'] =
&$this->b; }

Now it works as you expected.



Previous Comments:
------------------------------------------------------------------------

[2006-09-12 12:18:05] j dot henge-ernst at interexa dot de

Description:
------------
I encountered a problem similar to the bug #27268
http://bugs.php.net/bug.php?id=27268

The attribut b of the cloned object is still pointing to the attribut
of its original object. So changing the attribut in the cloned object
also changes the attribute in the original object.

Reproduce code:
---------------
<?php

class a {
    protected $a = array();
    protected $b = '';
    public function __construct($b) { $this->b = $b; $this->a['f'] =
&$this->b; }
    public function setB($b) { $this->b = $b; }
    public function printB() { echo __CLASS__ . $this->b . '/' .
$this->a['f'] ."\n"; }
    public function __clone() { unset($this->a['f']); $this->a['f'] =
&$this->b; }
}

$x1 = new a(5);
$x2 = clone $x1;
$x2->setB(7);
$x1->printB();
$x2->printB();



Expected result:
----------------
a5/5
a7/7

Actual result:
--------------
a7/7
a7/7


------------------------------------------------------------------------


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