ID:               40050
 Updated by:       [EMAIL PROTECTED]
 Reported By:      BenBE at omorphia dot de
-Status:           Open
+Status:           Bogus
 Bug Type:         Scripting Engine problem
 Operating System: Windows 2K
 PHP Version:      5.2.0
 New Comment:

Thank you for taking the time to write to us, but this is not
a bug. Please double-check the documentation available at
http://www.php.net/manual/ and the instructions on how to report
a bug at http://bugs.php.net/how-to-report.php

.


Previous Comments:
------------------------------------------------------------------------

[2007-01-07 19:57:47] BenBE at omorphia dot de

Description:
------------
When assigning an array by-value into itself PHP will insert a
self-referencing Array into the new entry

Reproduce code:
---------------
$a = array();
$a[] =& $a;
print_r($a);

$b = array();
$b[] = $b;
print_r($b);

Expected result:
----------------
array(1) {
  [0]=>
  array(1) {
    [0]=>
    array(1) {
      [0]=>
      *RECURSION*
    }
  }
}
array(1) {
  [0]=>
  array(0) {
  }
}
$b[0] should contain an empty array because $b was assigned by-value,
i.e. should get copied.

Actual result:
--------------
array(1) {
  [0]=>
  array(1) {
    [0]=>
    array(1) {
      [0]=>
      *RECURSION*
    }
  }
}
array(1) {
  [0]=>
  array(1) {
    [0]=>
    array(1) {
      [0]=>
      *RECURSION*
    }
  }
}

Comparing the references (see my entry regarding Spotting References)
you find that $b and $b[0] are different pointers and $b[0] is an array
like the one created in $a.


------------------------------------------------------------------------


-- 
Edit this bug report at http://bugs.php.net/?id=40050&edit=1

Reply via email to