Thanks Russell and Steve.

I forgot to add that this db call is working for about 5 other queries
strings. So far this is the only string that isn't working.

John

On Wed, 17 Jan 2001, Steve Brett wrote:

> don't know about mysql but in postgres echoing $the_call will return the id
> of the resource.
> 
> if you want the query result then you'll have to fetch that from $the_query
> using something like
> 
> $results = pg_fetch_array($thequery, 0) [substitute the mysql version of
> pg_fetch)
> 
> which will return the record at row 0 (result sets are zero indexed) as an
> associative array.
> 
> Steve
> 
> > -----Original Message-----
> > From: John Starkey [mailto:[EMAIL PROTECTED]]
> > Sent: 17 January 2001 09:19
> > To: [EMAIL PROTECTED]
> > Subject: [PHP-DB] MySQL looks cached.
> > 
> > 
> > I admit my newbie status but this is really odd even for me. :}
> > 
> > I'm returning an int from MySQL. No matter what that number is it's
> > returning as 3 until I refresh, when it becomes two. And on 
> > each refresh
> > after that it toggles between 2-3. 
> > 
> > I've checked my functions by redeclaring the var right after 
> > the db call
> > and everything is working fine. 
> > 
> > $the_query = "SELECT $something FROM somewhere WHERE 
> > RowName='$rowname'";
> > $the_call =  mysql($db, $the_query);
> > 
> > echo $the_call;
> > 
> > Will rturn 2's and 3's as i stated above. UNLESS i redeclare $the_call
> > before the echo.
> > 
> > Any see what I'm doing wrong?
> > 
> > Thanks,
> > 
> > John
> > 
> > 
> > 
> > 
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> 


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