K, I am using a script i found at hotscripts.com
I need it to upload an image to server.
I think that my issue is that i need to use the stripslashes(); somewhere, but i don't
know where
anyways here tis:
<?
function do_upload($filename,$newname) {
$file = basename($filename);
$tmp_upload_path = "c:/program files/apache group/apache/htdocs";
$new_file_name = "c:/program files/apache group/apache/htdocs".$newname;
$file = stripslashes($file);
$tmp_upload_path = stripslashes($tmp_upload_path);
$new_file_name = stripslashes($new_file_name);
if (!copy($tmp_upload_path.$file, $new_file_name)) echo "failed to copy file<br>\n";
return;
}
?>
and later i calll the function:
<? do_upload($userfile,$newname); ?>
here the error i receive:
Warning: Unable to open 'c:/program files/apache group/apache/htdocsphp2' for reading:
No such file or directory in c:\program files\apache
group\apache\htdocs\uploads\2\upload_go.php on line 9
and script returns this
upload tmp file: \\php2
There is an article at phpbuilder called file uploading made easy
http://phpbuilder.com/columns/bealers20000904.php3
i am having the same issues with this script and though i found an answer to the
file://php2 thing [it was a stripslashes() solution] I am getting an error with this
script that there is an unset variable... It looks set to me :)
puzzled,
olinux [who thanks you all greatly]
