Hi,
i don't get that.
Examlpe: tablename: test , entry: id 001; name: John Doe
$result = mysql_query("SELECT * FROM test");
$row = mysql_fetch_whatever($result); // everything ok
$result = mysql_query("SELECT * FROM tet");
$row = mysql_fetch_wahtever($result); // Warning: Supplied arggument is not
a valid ....
$result = mysql_query("SELECT nonexistent FROM test");
$row = mysql_fetch_whatever($result); // Warning: Supplied argument is not
....
$result = mysql_query("SELECT * FROM test WHERE id='002'");
$row = mysql_fetch_whatever($result); // no errormsg, $result=true but empty
That's what I get. So there must be something wrong with the query.
Johannes
""Klaus Haberkorn"" <[EMAIL PROTECTED]> schrieb im Newsbeitrag
9bhh1c$2gg$[EMAIL PROTECTED]">news:9bhh1c$2gg$[EMAIL PROTECTED]...
> thank You, Johannes,
> but I think we can skip this,
> we reduced the query statement to the most simple one:
> "SELECT * FROM {tablename}"
> if the tablename is wrong, then another error message is issued.
> the result is not treated by a while-loop but just by fetch_num_rows,
> which at least reports the error.
> (and, by the way, the same script runs on another system)
> so we are more looking for problems with apache versions
> and/or modules.
> we also checked access-rights, but this also causes different errors.
> any other idea?
>
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