Hello, I have pictures stored in a database, when I will see them I get only placeholder of pictures but not the picture self. What is wrong in my code? Please help me. Code section: 1) PHP-HTML for storing: <? if (!isset($img1)) { header("Location: http://localhost/php/insert_file.html"); exit; } $db = mysql_connect() or die("Can't connect to server."); mysql_select_db("media", $db) or die("Can't select database."); $binary_junk = addslashes(fread(fopen($img1, "r"), filesize($img1))); $insert_data = "INSERT INTO images(img_id, binary_junk, filename, filesize, filetype) VALUES ('4', '$binary_junk', '$img1_name', '$img1_size', '$img1_type')"; mysql_query($insert_data) or die("Couldn't insert data."); ?> <HTML> <HEAD> <TITLE>Successful File Insertion!</TITLE> <BODY> <H1>Success!</H1> <P>You have inserted the following into your database:<br> <? echo "$img1_name"; ?>, a <? echo "$img1_size"; ?> byte file with a mime type of <? echo "$img1_type"; ?>.</P> </BODY> </HTML> 2) Html for viewing: <HTML> <HEAD> <TITLE>My Image</TITLE> </HEAD> <BODY> <H1>Look at this:</H1> <IMG SRC="show_image2.php"> </BODY> </HTML> 3) PHP for viewing: <? $db = mysql_connect(); $sqlab = "select img_id, filename, binary_junk, filetype from images"; $res = mysql_db_query("media", $sqlab); $num = mysql_num_rows($res); if ($num==0) echo "Leider wurden keine Bilder gefunden<br>"; for($i=0; $i<$num; $i++) { $id = mysql_result($res, $i, "img_id"); $fn = mysql_result($res, $i, "filename"); $ft = mysql_result($res, $i, "filetype"); $bj = mysql_result($res, $i, "binary_junk"); header("Content-type: $ft"); echo "$bj" . "<p>"; } mysql_close($db); ?> Thanks for your help. Damian -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] To contact the list administrators, e-mail: [EMAIL PROTECTED]